Core Reactions: Balancing Redox Equations
Slide 15 of 29
A Note on the two Oxidizing Agents
Have a look at the balanced half equations for the reduction of dichromate(VI) and managate(VII) ions:
–Cr2O72-  + 14H+ + 6e-  ®  2Cr3+ + 7H2O
–MnO42- + 8H+  + 5e- ®  Mn2+ + 4H2O
When the reducing agent is one without any oxygen (as in the example considered, Cl-) notice that the number of hydrogen ions and water molecules in the balanced half-equations are dictated by the number of oxygen in the oxidizing agent.
And therefore, the number of hydrogen ions and water in the final balanced equation is a multiple of that.
•Cr2O72- (aq) + 14H+ (aq) + 6Cl- (aq)    ®  3Cl2 (g) + 2Cr3+ (aq) + 7H2O (l)
–1´ that in the reduction half-equation.
•2MnO42- (aq) + 10Cl- (aq) + 16H+ (aq) ®  2Mn2+ (aq) + 5Cl2 (aq) + 8H2O (l)
–2´ that in the balanced reduction half-equation.
Not only that, the balanced half equations appear on page 19 of the Data Booklet.